How to print variable name in C?

Before going to write C program for this problem, I would like to tell about the stringizing operator in C?

The operator # is known as the stringizing operator in C. The stringizing operator (#) converts, its argument in a string.

Method 1: Here is the C program to print variable name using a single line macro and stringizing operator.

/* 
 * Method 1 : To print variable name using single line MACRO 
 * and stringizing operator 
 */
#include <stdio.h>  
#define printVar(varName) #varName
int main ()  
{  
   int acTestVar;  
   printf("%s\n", printVar(acTestVar));  
   return 0;  
}  

Method 2: Here is the C program to print variable name using a multiline macro and stringizing operator & storing variable name in strBuf using sprintf(), then printing it.

/*
 * Method 2 : To print variable name using multiline MACROs
 * stringizing operator & storing variable in strBuf using sprintf()
 */
#include <stdio.h>  
#define printVar(varName,strBuf){\
        sprintf(strBuf,"%s\n",#varName);\
        printf("%s", strBuf);\
        }
int main ()  
{  
    int acTestVar;  
    char strBuf[32];
    printVar(acTestVar, strBuf);
    return 0;  
}  

Method 3: Here is the C program to print variable name using a single line macro and stringizing operator & storing variable name in strBuf using sprintf(), then printing it.

/*
 * Method 3 : To print variable name using single MACROs
 * stringizing operator & storing variable in strBuf using sprintf()
 */
#include <stdio.h>  
#define printVar(varName,strBuf) sprintf(strBuf,"%s\n",#varName)
int main()  
{  
   int acTestVar;
   char strBuf[32];
   printVar(acTestVar, strBuf);
   printf("%s", strBuf);
   return 0;
}  

Hope, it would be helpful .

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